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키움 수식 변경 부탁 드립니다.

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이름이
2021-11-19 16:47:43
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글번호 153755
답변완료
period = 130 CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*2) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*4) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*6) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*8) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*10)
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예스스탁 예스스탁 답변

2021-11-22 09:51:27

안녕하세요 예스스탁입니다. input : Period(130); var : CL(0); var1 = Highest(H,Period); Var2 = Lowest(L,Period); if var1[1] < var1 Then CL = (var1+var2)/2; value1 = var1-(((var1-CL)/5)*2); value2 = var1-(((var1-CL)/5)*4); value3 = var1-(((var1-CL)/5)*6); value4 = var1-(((var1-CL)/5)*8); value5 = var1-(((var1-CL)/5)*10); Plot1(value1); Plot2(value2); Plot3(value3); Plot4(value4); Plot5(value5); 즐거운 하루되세요 > 이름이 님이 쓴 글입니다. > 제목 : 키움 수식 변경 부탁 드립니다. > period = 130 CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*2) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*4) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*6) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*8) CL=valuewhen(1,(highest(h(1),period)<highest(h,period)),((highest(high,Period)+lowest(low,Period))/2)); highest(H, period)-(((highest(H, period)-CL)/5)*10)