답변완료
수식 부탁드립니다.
1. 하기 내용의 지표를 수식으로 부탁드립니다
A1D=LowestSince(1,CrossDown(Trix(N1),0),avg(가격,N2,이평종류));
A1U=LowestSince(1,CrossUp(Trix(N3),0),avg(가격,N4,이평종류));
B1D=HighestSince(1,CrossDown(Trix(N5),0),avg(가격,N6,이평종류));
B1U=HighestSince(1,CrossUp(Trix(N7),0),avg(가격,N8,이평종류));
가격(C), N1(13), N2(5), N3(13), N4(10), N5(12), N6(5), N7(12), N8(10), 이평종류(지수)
2. A1D선을 상향돌파한것이 최근 3봉이내에 1회이상이면서 A1U선을 상향돌파할 때의 매수신호로서 추가적조건으로 종가는 5지수이평선보다 높아야하고, 고가는 B1U보다 낮아야 하며, 위의 신호는 최근 10봉이내에 처음이어야 한다는 조건을 반영한 매수신호수식
2023-02-22
1612
글번호 166549
지표
답변완료
지표
항상감사합니다.
수식의 진동폭의 1/10의 값만표시됩니다.
진동폭6
1/10=1[0.6]
5/10=5[0.6]모두 이렇게 나옵니다.
1]계산된 진동폭부탁드립니다.
진동폭6이라면
1/10은 [0.6]가격
2/10은 [0.3]가격
부탁드립니다.
Input : 진동폭(6);
var : tx1(0);
var : tx10(0),tx11(0),tx12(0),tx13(0),tx14(0),
tx15(0),tx16(0),tx17(0),tx18(0),tx19(0);
var : tx20(0),tx21(0),tx22(0),tx23(0),tx24(0),
tx25(0),tx26(0),tx27(0),tx28(0),tx29(0);
var1 = DayOpen;
value1 = 진동폭/10;
Plot1(var1);
plot10(var1+value1*1);
plot11(var1+value1*2);
plot12(var1+value1*3);
plot13(var1+value1*4);
plot14(var1+value1*5);
plot15(var1+value1*6);
plot16(var1+value1*7);
plot17(var1+value1*8);
plot18(var1+value1*9);
plot19(var1+value1*10);
plot20(var1-value1*1);
plot21(var1-value1*2);
plot22(var1-value1*3);
plot23(var1-value1*4);
plot24(var1-value1*5);
plot25(var1-value1*6);
plot26(var1-value1*7);
plot27(var1-value1*8);
plot28(var1-value1*9);
plot29(var1-value1*10);
Text_Delete(tx1);
Text_Delete(tx10);
Text_Delete(tx11);
Text_Delete(tx12);
Text_Delete(tx13);
Text_Delete(tx14);
Text_Delete(tx15);
Text_Delete(tx16);
Text_Delete(tx17);
Text_Delete(tx18);
Text_Delete(tx19);
Text_Delete(tx20);
Text_Delete(tx21);
Text_Delete(tx22);
Text_Delete(tx23);
Text_Delete(tx24);
Text_Delete(tx25);
Text_Delete(tx26);
Text_Delete(tx27);
Text_Delete(tx28);
Text_Delete(tx29);
tx1 = Text_New(NextBarSdate,NextBarStime,var1," ["+NumToStr(진동폭,1)+"]");
tx10 = Text_New(NextBarSdate,NextBarStime,var1+value1*1," 1["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*1,2));
tx11 = Text_New(NextBarSdate,NextBarStime,var1+value1*2," 2["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*2,2));
tx12 = Text_New(NextBarSdate,NextBarStime,var1+value1*3," 3["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*3,2));
tx13 = Text_New(NextBarSdate,NextBarStime,var1+value1*4," 4["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*4,2));
tx14 = Text_New(NextBarSdate,NextBarStime,var1+value1*5," 5["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*5,2));
tx15 = Text_New(NextBarSdate,NextBarStime,var1+value1*6," 6["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*6,2));
tx16 = Text_New(NextBarSdate,NextBarStime,var1+value1*7," 7["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*7,2));
tx17 = Text_New(NextBarSdate,NextBarStime,var1+value1*8," 8["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*8,2));
tx18 = Text_New(NextBarSdate,NextBarStime,var1+value1*9," 9["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*9,2));
tx19 = Text_New(NextBarSdate,NextBarStime,var1+value1*10," 10["+NumToStr(Value1,2)+"]"+NumToStr(var1+value1*10,2));
tx20 = Text_New(NextBarSdate,NextBarStime,var1-value1*1," 1["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*1,2));
tx21 = Text_New(NextBarSdate,NextBarStime,var1-value1*2," 2["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*2,2));
tx22 = Text_New(NextBarSdate,NextBarStime,var1-value1*3," 3["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*3,2));
tx23 = Text_New(NextBarSdate,NextBarStime,var1-value1*4," 4["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*4,2));
tx24 = Text_New(NextBarSdate,NextBarStime,var1-value1*5," 5["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*5,2));
tx25 = Text_New(NextBarSdate,NextBarStime,var1-value1*6," 6["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*6,2));
tx26 = Text_New(NextBarSdate,NextBarStime,var1-value1*7," 7["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*7,2));
tx27 = Text_New(NextBarSdate,NextBarStime,var1-value1*8," 8["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*8,2));
tx28 = Text_New(NextBarSdate,NextBarStime,var1-value1*9," 9["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*9,2));
tx29 = Text_New(NextBarSdate,NextBarStime,var1-value1*10," 10["+NumToStr(Value1,2)+"]"+NumToStr(var1-value1*10,2));
2023-02-22
1074
글번호 166544
지표